(4/9)^x+(8)^1-x=486

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Solution for (4/9)^x+(8)^1-x=486 equation: 



(4/9)^x+(8)^1-x=486

We move all terms to the left:

(4/9)^x+(8)^1-x-(486)=0



Domain of the equation: 9)^x!=0

x!=0/1

x!=0

x∈R



determiningTheFunctionDomain
(4/9)^x-x-486+8^1=0

We add all the numbers together, and all the variables

(+4/9)^x-x-486+8^1=0

We add all the numbers together, and all the variables

-1x+(+4/9)^x-478=0

We multiply all the terms by the denominator


-1x*9)^x+(-478*9)^x+4=0

We add all the numbers together, and all the variables

-1x*9)^x+(-4302)^x+4=0

Wy multiply elements

-9x^2-4302)^x+4=0

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